# This is my shopping list
shoplist = ['apple', 'mango', 'carrot', 'banana']
print('I have', len(shoplist), 'items to purchase.')
print('These items are:', end=' ')
for item in shoplist:
print(item, end=' ')
print('\nI also have to buy rice.')
shoplist.append('rice')
print('My shopping list is now', shoplist)
print('I will sort my list now')
shoplist.sort()
print('Sorted shopping list is', shoplist)
print('The first item I will buy is', shoplist[0])
olditem = shoplist[0]
del shoplist[0]
print('I bought the', olditem)
print('My shopping list is now', shoplist)
输出:
$ python ds_using_list.py
I have 4 items to purchase.
These items are: apple mango carrot banana
I also have to buy rice.
My shopping list is now ['apple', 'mango', 'carrot', 'banana', 'rice']
I will sort my list now
Sorted shopping list is ['apple', 'banana', 'carrot', 'mango', 'rice']
The first item I will buy is apple
I bought the apple
My shopping list is now ['banana', 'carrot', 'mango', 'rice']
随后,当我们当我们在市场上买回某件商品时,我们需要从列表中移除它。我们通过使用 del 语句来实现这一需求。在这里,我们将给出我们希望从列表中移除的商品,del 语句则会为我们从列表中移除对应的项目。我们希望移除列表中的第一个商品,因此我们使用 del shoplist[0](要记住 Python 从 0 开始计数)。
# 我会推荐你总是使用括号
# 来指明元组的开始与结束
# 尽管括号是一个可选选项。
# 明了胜过晦涩,显式优于隐式。
zoo = ('python', 'elephant', 'penguin')
print('Number of animals in the zoo is', len(zoo))
new_zoo = 'monkey', 'camel', zoo
print('Number of cages in the new zoo is', len(new_zoo))
print('All animals in new zoo are', new_zoo)
print('Animals brought from old zoo are', new_zoo[2])
print('Last animal brought from old zoo is', new_zoo[2][2])
print('Number of animals in the new zoo is',
len(new_zoo)-1+len(new_zoo[2]))
输出:
$ python ds_using_tuple.py
Number of animals in the zoo is 3
Number of cages in the new zoo is 3
All animals in new zoo are ('monkey', 'camel', ('python', 'elephant', 'penguin'))
Animals brought from old zoo are ('python', 'elephant', 'penguin')
Last animal brought from old zoo is penguin
Number of animals in the new zoo is 5
它是如何工作的
变量 zoo 指的是一个包含项目的元组。我们能够看到 len 函数在此处用来获取元组的长度。这也表明元组同时也是一个序列。
# “ab”是地址(Address)簿(Book)的缩写
ab = {
'Swaroop': 'swaroop@swaroopch.com',
'Larry': 'larry@wall.org',
'Matsumoto': 'matz@ruby-lang.org',
'Spammer': 'spammer@hotmail.com'
}
print("Swaroop's address is", ab['Swaroop'])
# 删除一对键值—值配对
del ab['Spammer']
print('\nThere are {} contacts in the address-book\n'.format(len(ab)))
for name, address in ab.items():
print('Contact {} at {}'.format(name, address))
# 添加一对键值—值配对
ab['Guido'] = 'guido@python.org'
if 'Guido' in ab:
print("\nGuido's address is", ab['Guido'])
输出:
$ python ds_using_dict.py
Swaroop's address is swaroop@swaroopch.com
There are 3 contacts in the address-book
Contact Swaroop at swaroop@swaroopch.com
Contact Matsumoto at matz@ruby-lang.org
Contact Larry at larry@wall.org
Guido's address is guido@python.org
shoplist = ['apple', 'mango', 'carrot', 'banana']
name = 'swaroop'
# Indexing or 'Subscription' operation #
# 索引或“下标(Subscription)”操作符 #
print('Item 0 is', shoplist[0])
print('Item 1 is', shoplist[1])
print('Item 2 is', shoplist[2])
print('Item 3 is', shoplist[3])
print('Item -1 is', shoplist[-1])
print('Item -2 is', shoplist[-2])
print('Character 0 is', name[0])
# Slicing on a list #
print('Item 1 to 3 is', shoplist[1:3])
print('Item 2 to end is', shoplist[2:])
print('Item 1 to -1 is', shoplist[1:-1])
print('Item start to end is', shoplist[:])
# 从某一字符串中切片 #
print('characters 1 to 3 is', name[1:3])
print('characters 2 to end is', name[2:])
print('characters 1 to -1 is', name[1:-1])
print('characters start to end is', name[:])
输出:
$ python ds_seq.py
Item 0 is apple
Item 1 is mango
Item 2 is carrot
Item 3 is banana
Item -1 is banana
Item -2 is carrot
Character 0 is s
Item 1 to 3 is ['mango', 'carrot']
Item 2 to end is ['carrot', 'banana']
Item 1 to -1 is ['mango', 'carrot']
Item start to end is ['apple', 'mango', 'carrot', 'banana']
characters 1 to 3 is wa
characters 2 to end is aroop
characters 1 to -1 is waroo
characters start to end is swaroop
print('Simple Assignment')
shoplist = ['apple', 'mango', 'carrot', 'banana']
# mylist 只是指向同一对象的另一种名称
mylist = shoplist
# 我购买了第一项项目,所以我将其从列表中删除
del shoplist[0]
print('shoplist is', shoplist)
print('mylist is', mylist)
# 注意到 shoplist 和 mylist 二者都
# 打印出了其中都没有 apple 的同样的列表,以此我们确认
# 它们指向的是同一个对象
print('Copy by making a full slice')
# 通过生成一份完整的切片制作一份列表的副本
mylist = shoplist[:]
# 删除第一个项目
del mylist[0]
print('shoplist is', shoplist)
print('mylist is', mylist)
# 注意到现在两份列表已出现不同
输出:
$ python ds_reference.py
Simple Assignment
shoplist is ['mango', 'carrot', 'banana']
mylist is ['mango', 'carrot', 'banana']
Copy by making a full slice
shoplist is ['mango', 'carrot', 'banana']
mylist is ['carrot', 'banana']
# 这是一个字符串对象
name = 'Swaroop'
if name.startswith('Swa'):
print('Yes, the string starts with "Swa"')
if 'a' in name:
print('Yes, it contains the string "a"')
if name.find('war') != -1:
print('Yes, it contains the string "war"')
delimiter = '_*_'
mylist = ['Brazil', 'Russia', 'India', 'China']
print(delimiter.join(mylist))
输出:
$ python ds_str_methods.py
Yes, the string starts with "Swa"
Yes, it contains the string "a"
Yes, it contains the string "war"
Brazil_*_Russia_*_India_*_China